/*
return an array of years with n number of years before or after current year
$before = how many years before current year
$after = how many years after current year
*/
function yearArray($before, $after)
{
$yr = date("Y");
$start = $yr - $before;
$end = $yr + $after;
$aY = array();
for($x = $start; $x <= $end; $x++) {
$aY[] = ($x);
}
return $aY;
}